4x^2-132x+272=0

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Solution for 4x^2-132x+272=0 equation:



4x^2-132x+272=0
a = 4; b = -132; c = +272;
Δ = b2-4ac
Δ = -1322-4·4·272
Δ = 13072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{13072}=\sqrt{16*817}=\sqrt{16}*\sqrt{817}=4\sqrt{817}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-132)-4\sqrt{817}}{2*4}=\frac{132-4\sqrt{817}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-132)+4\sqrt{817}}{2*4}=\frac{132+4\sqrt{817}}{8} $

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